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Home / Doubts and Solutions/JEE/Mathematics

The Equation ax^2+bx+c=0 has sin(theta) and cos(theta) as its roots, then find the value of 

(a+c)^2/b^2+c^2.

Asked by Anish 16th October 2018, 11:26 PM
Answered by Expert
Answer:
begin mathsize 18px style roots space are space sinθ space and space cosθ sum space of space roots equals space sinθ space plus space cosθ space equals space fraction numerator negative straight b over denominator straight a end fraction product space of space roots equals space sinθ space. cosθ space equals space straight c over straight a open parentheses sinθ space plus space cosθ space close parentheses squared equals sin squared straight theta plus cos squared straight theta plus 2 sinθ space. cosθ open parentheses sinθ space plus space cosθ space close parentheses squared equals 1 plus 2 sinθ space. cosθ sub..... end style
Answered by Expert 22nd October 2018, 5:14 PM
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