the enthalpy of formation of methane of constant pressure and 300 K is 78.84 KJ. What will be the enthalpy of formation at constant volume ?
Asked by निकोदिमुस
4th October 2017,
6:15 PM
Answered by Expert
Answer:
The equation for the formation of methane is,
C(s) + 2H2(g) = CH4(g) ; ΔH = –75.83 kJ
2 mole 1 mole
Δn = (1 – 2) = –1
Given,
ΔH = –75.83 kJ,
R = 8.3 × 10–3 kJ K–1 mol–1
T = 300 K
Applying, ΔH = ΔE + ΔnRT
–75.83 = ΔE + (–1) (8.3 × 10–3) (300)
ΔE = –75.83 + 2.49
= –73.34 kJ
Answered by Expert
5th October 2017,
11:20 AM
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