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CBSE Class 12-science Answered

the energy level of hypothetical atom is 0ev -2ev -4.5ev -10ev the A reaches to level -2ev from 0 ev while B from 0ev to -4.5ev C:from -2ev to -4.5ev and D from -2 to -10ev. which of the above will show transition will result in the emission of photon of wavelength of 275nm? which of these transistion coressponds to the emission of radiation of maximum and minimum?                                                                    
Asked by vasturushi | 28 Feb, 2018, 02:30: AM
answered-by-expert Expert Answer
Energy of 275 nm photon = hc/λ, where h is plancks constant, c is velocity of light and λ is wavelength of photon.
 
Energy of 275 nm photon = (6.626×10-34×3×108) / (275×10-9) = 7.228×10-19 Joules
 
1 eV = 1.602×10-19 Joules
 
Energy of 275 nm photon in eV = (7.228×10-19) / (1.602×10-19) = 4.51 eV. 
 
B , which is raised from 0 to -4.5eV will give 275 nm radiation
 
transition between 0 eV and -2 eV will give radiation emission of minmum energy 
transition between 0 eV and -10 eV will give radiation emission of maximum energy 
Answered by Thiyagarajan K | 28 Feb, 2018, 12:29: PM

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