NEET Class neet Answered
the emf of a battery by a length of 80 cm on a potentiometer wire
Asked by mdhanush411 | 07 Jan, 2021, 06:59: AM
Expert Answer
Potential difference across A and B is given as, VAB = VAC + VCD + VDE + VEB
where VAC = 2 V , potential difference across A and C ,
VCD = 1 A × 2 Ω = 2 V , potential difference across C and D ,
VDE = -5 V , potential difference across D and E ,
VEB = 1 A × 1 Ω = 1 V , potential difference across E and B
VAB = VAC + VCD + VDE + VEB = ( 2 + 2 -5 +1 ) = 0 V
Answered by Thiyagarajan K | 07 Jan, 2021, 09:07: AM
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