Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 11-science Answered

The displacement x of a particle varies with time t as x=4t²-15t+25. Find the position, velocity and acceleration of a particle become zero? Can we call the motion of the particle as one with uniform acceleration?
Asked by mr.perfect420 | 19 May, 2019, 08:53: AM
answered-by-expert Expert Answer
Let us assume SI units are to be used

position x = ( 4t2 -15t + 25 )  m
 
velocity  dx/dt  = ( 8t - 15 ) m/s
 
acceleration = 8  m/s2
 
Since acceleration is constant, this motion is uniformly accelerated motion.
 
velocity will become zero when t = 15/8 seconds
 
at t = 15/8 s, when velocity becomes zero, position of particle  = 4×(15/8)2 -15(15/8) +25 ≈ 11 m
Answered by Thiyagarajan K | 19 May, 2019, 10:36: AM
CBSE 11-science - Physics
Asked by sumedhasingh238 | 28 Mar, 2024, 11:10: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by roshnibudhrani88 | 23 Mar, 2024, 05:52: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by rosysahu678 | 02 Mar, 2024, 06:09: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by vaddevenkatesulu56 | 26 Feb, 2024, 09:02: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by rustampathan | 25 Feb, 2024, 06:39: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Physics
ans
question image
Asked by hjha9709 | 25 Feb, 2024, 12:13: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
Get Latest Study Material for Academic year 24-25 Click here
×