CBSE Class 11-science Answered
The displacement x of a particle varies with time t as x=4t²-15t+25.
Find the position, velocity and acceleration of a particle become zero? Can we call the motion of the particle as one with uniform acceleration?
Asked by mr.perfect420 | 19 May, 2019, 08:53: AM
Expert Answer
Let us assume SI units are to be used
position x = ( 4t2 -15t + 25 ) m
velocity dx/dt = ( 8t - 15 ) m/s
acceleration = 8 m/s2
Since acceleration is constant, this motion is uniformly accelerated motion.
velocity will become zero when t = 15/8 seconds
at t = 15/8 s, when velocity becomes zero, position of particle = 4×(15/8)2 -15(15/8) +25 ≈ 11 m
Answered by Thiyagarajan K | 19 May, 2019, 10:36: AM
CBSE 11-science - Physics
Asked by sumedhasingh238 | 28 Mar, 2024, 11:10: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by roshnibudhrani88 | 23 Mar, 2024, 05:52: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by emad.amd | 21 Mar, 2024, 12:00: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by vinitdubey7735 | 14 Mar, 2024, 11:21: AM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by om636694 | 04 Mar, 2024, 09:10: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by rajuinwati12 | 04 Mar, 2024, 09:22: AM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by rosysahu678 | 02 Mar, 2024, 06:09: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by vaddevenkatesulu56 | 26 Feb, 2024, 09:02: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by rustampathan | 25 Feb, 2024, 06:39: PM
ANSWERED BY EXPERT