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The change in entropy of 2 moles of an ideal gas upon isothermal expansion at 243.6k from 20 litre until the pressure becomes 1atm is

Asked by m.nilu 25th September 2018, 1:41 PM
Answered by Expert
Answer:
The change in entropy of 2 moles of an ideal gas upon isothermal expansion at 243.6k from 20 litre until the pressure becomes 1atm is
 
Given:
 
Pi = 1 atm
 
No. of moles = 2 mol
 
T = 243.6 K
 
V = 20 litre
 
We know,
 
PV = nRT
 
 
straight P space equals nRT over straight V

space space space equals fraction numerator 2 cross times 0.0821 cross times 243.6 over denominator 20 end fraction

space straight P space equals space 2 space atm

increment straight S space equals space minus 4 Rln straight P subscript 2 over straight P subscript 1

space space space space space space space equals space 2 cross times fraction numerator 8.314 over denominator 4.19 end fraction ln space 2 over 1

space space space space space space space equals 2 cross times 0.6931 cross times 1.9

increment straight S space equals 2.77 space cal divided by straight K
Change in entropy is 2.77 cal/K
Answered by Expert 25th September 2018, 7:31 PM
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