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the available nitrogen in 100 kj urea samle is found to be 35% by weight. the actual urea content in sample  will be?

Asked by imtiyazmulla68 19th November 2017, 7:32 PM
Answered by Expert
Answer:
Molecular space weight space of space urea space equals space 60
35 percent sign space nitrogen space by space weight comma
60 cross times 35 over 100 equals 21
Actual space urea space content equals 60 minus 21
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 39
For space 100 space kg space urea
fraction numerator 100 cross times 10 cubed space straight g cross times 39 over denominator 60 end fraction space equals space 6.55 cross times 10 to the power of 4 space straight g
space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 65.5 space kg
Answered by Expert 20th November 2017, 4:11 PM
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