ICSE Class 8 Answered
The amount of heat absorbed by 1g of water while vapourising?
Asked by Spankinaishu | 07 Jun, 2018, 08:28: PM
Expert Answer
Heat absorbed while vapouraisation = m×Cp×ΔT + m×Lv .............(1)
where m is mass of water = 1 g = 10-3 kg
Cp is specific heat of water = 4200 J/(kg.K)
ΔT is temperature difference = (100-20) °C = 353 K ( initial temperature is assumed as 20 °C)
Lv is latent heat of vapouraisation = 2260 kJ / kg
Substitute all the data in Eqn.(1) to get the answer 3743 J
Answered by Thiyagarajan K | 08 Jun, 2018, 10:48: AM
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