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CBSE - X - Mathematics - Surface Areas and Volumes

surface area volume

Asked by akhileshnarayanan 12th March 2010, 2:34 PM
Answered by Expert

Answer:

A MILK CONTAINER WILL BE A CLOSED VESSEL SO WE NEED TO TAKE IT'S TSA.

Volume of frustrum = (1/3)πh(r12+r22+r1r2) = 31380/7

(1/3)(22/7)h(202+82+160) = 31380/7

(1/3)(22)h(202+82+160) = 31380

h = 31380x3/(22x624) =  6.86

l = (h2+(r1 - r2)2)  = 13.82

TSA of frustrum = πr12 + πr22 + πl(r1+r2) = (3.14)(202+82+(13.83(28)) = 2672 cm2

Cost of making the container = 2672x1.40 = Rs 3740.83.

Regards,

Team,

TopperLearning.

 

Answered by Expert 13th March 2010, 7:04 AM

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