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stone of 1kg is thrown with a velocity of 20m/s across the frozen surface of lake and comes to rest after travelling a distance if 50m. what is the force of friction between the stone and the ice

Asked by 28th July 2012, 11:49 AM
Answered by Expert
Answer:
Let force of friction be F
Thus deceleration produced by that force would be F/m = F (m=1kg)
using 3rd equation of motion:
Answered by Expert 28th July 2012, 2:21 PM
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