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steam  at 100 degree celsius is passed into 1 kg of water contained in a calorimeter at 9 degree celsius till the temperature of water and calorimeter is increased to 90 degree celsius. The mass of steam condensed is nearly ( water equivalent of calorimeter =0.1 kg specific heat of water =1calg-1degree celsius inverse and latent heat of vaporisation =540calg-1
Asked by Charishmachowdari0909 | 30 Mar, 2019, 09:42: AM
answered-by-expert Expert Answer
Let x be the mass of steam condensed. The heat obtained calorimeter with water is equal the heat from condensing x kg of steam and the heat from cooling x kg of water to the final temperature of calorimeter with water. x∙L + x∙c∙(T3 − T2 ) = (m + mc)∙c∙(T2 − T1 ), where L = 540 cal/g – latent heat of steam, c = 1 cal/g∙degree – specific heat of water,Read more on Sarthaks.com - https://www.sarthaks.com/106929/steam-at-100c-is-passed-into-1-1-kg-of-water-contained-in-a-calorimeter
Answered by Ankit K | 31 Mar, 2019, 08:17: PM
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