CBSE Class 8 Answered
Squares of two consecutive natural numbers are considered. There exists 16 non-perfect square numbers between them. Express the greater of the two square numbers as sum of two natural numbers.
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
Expert Answer
Given that, between the squares of two consecutive natural numbers, there exists 16 non-perfect square numbers.
We know that there are 2n non-perfect square numbers between n2 and (n+1)2.
Thus, 16 = 2x8 non-perfect square numbers exists between 82 and 92.
Now, we need to express the greater of the two square numbers, that is, 92 as the sum of two natural numbers.
Now, 
Answered by | 04 Jun, 2014, 03:23: PM
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