Please wait...
Contact Us
Contact
Need assistance? Contact us on below numbers

For Study plan details

10:00 AM to 7:00 PM IST all days.

For Franchisee Enquiry

OR

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this number

9321924448

Mon to Sat - 10 AM to 7 PM

Someone pls do this

qsnImg
Asked by pukai7229 2nd November 2018, 11:00 PM
Answered by Expert
Answer:
Required changes for the ice to convert from -12°C ice to 100°C steam 
(1) Conversion of ice from -12°C to ice at 0 °C
(2) conversion of ice at 0 °C to water at 0 °C (latent heat of fusion)
(3) Change of water temperature from 0 °C to 100 °C
(4) Change of water from 100 °C to steam at 100 °C (latent heat of vaporaisation)
 
Heat energy required for Conversion of ice from -12°C to ice at 0 °C = mass×specific heat×Temperature increase
                                                                                                            = 3 × 2.1×105 × 12 = 75.6×105 J ................................................(1)
Heat energy required for conversion of ice at 0 °C to water at 0 °C = 3×3.35×105 = 10.05×105 J ...........................................(2)
 
Heat energy required for Change of water temperature from 0 °C to 100 °C = 3×4.186×103 × 100  = 12.558×105 ..................(3)
Heat energy required for Change of water from 100 °C to steam at 100 °C = 3×2.256×106  = 6.768×106 J ......................(4)
 
By adding all heat energy from eqn.(1) to eqn.(4), we get total heat energy = 16.59 ×106 J
Answered by Expert 3rd November 2018, 3:48 AM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Tags: heat-energy
Your answer has been posted successfully!

Chat with us on WhatsApp