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Home / Doubts and Solutions/JEE/Mathematics

Someone please solve this quadratic equation!! 

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Asked by pukai7229 30th June 2018, 11:15 AM
Answered by Expert
Answer:
begin mathsize 16px style square root of fraction numerator 4 straight x minus 1 over denominator 4 straight x plus 1 end fraction end root minus square root of fraction numerator 4 straight x plus 1 over denominator 4 straight x minus 1 end fraction end root equals 8 over 3 Consider space square root of fraction numerator 4 straight x minus 1 over denominator 4 straight x plus 1 end fraction end root equals straight y rightwards double arrow square root of fraction numerator 4 straight x plus 1 over denominator 4 straight x minus 1 end fraction end root equals 1 over straight y straight y minus 1 over straight y equals 8 over 3 3 open parentheses straight y squared minus 1 close parentheses equals 8 straight y 3 straight y squared minus 8 straight y minus 3 equals 0 3 straight y squared minus 9 straight y plus straight y minus 3 equals 0 3 straight y open parentheses straight y minus 3 close parentheses plus left parenthesis straight y minus 3 right parenthesis equals 0 left parenthesis straight y minus 3 right parenthesis left parenthesis 3 straight y plus 1 right parenthesis equals 0 straight y equals 3 space or space straight y equals fraction numerator negative 1 over denominator 3 end fraction square root of fraction numerator 4 straight x minus 1 over denominator 4 straight x plus 1 end fraction end root equals 3 space or space square root of fraction numerator 4 straight x minus 1 over denominator 4 straight x plus 1 end fraction end root equals fraction numerator negative 1 over denominator 3 end fraction Solve space it space further space to space get space the space value space of space straight x end style
Answered by Expert 3rd July 2018, 5:53 PM
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