NEET Class neet Answered

⭕ Solve this question by using the relation between power gain & voltage gain. [ Power gain= voltage gain × ß] where, ß = current gain=(Ic/ib) thanks🙂

Asked by jhajuhi19 | 24 Apr, 2020, 08:16: AM

Expert Answer

Power gain = 800

Voltage amplification factor = 840

Collector current, i_C = 12 mA

A s space t h i s space i s space t r a n s i s t o r space a s space a space C B space a m p l i f i e r comma space C u r r e n t space g a i n space i s space g i v e n space a s comma space alpha space equals space fraction numerator P o w e r space g a i n over denominator V o l t a g e space g a i n end fraction space equals space 800 over 840 space equals space 0.95 space... space left parenthesis 1 right parenthesis N o w comma space w i t h space t j i s space w e space c a n space f i n d space beta comma space R e l a t i o n space b e t w e e n space alpha space a n d space beta space i s space g i v e n space a s comma space beta equals fraction numerator alpha over denominator 1 minus alpha end fraction space equals space fraction numerator 0.95 space over denominator 1 minus 0.95 end fraction space... space left parenthesis f r o m space left parenthesis 1 right parenthesis right parenthesis space beta equals space fraction numerator 0.95 over denominator 1 minus 0.95 end fraction space equals 19 space beta equals i subscript c over i subscript b space rightwards double arrow 19 equals fraction numerator i subscript c over denominator 12 space m A end fraction rightwards double arrow i subscript c equals 19 space cross times space 12 space equals space 228 space m A space

Thus, the collector current is 228 mA when the base current is 12 mA

Answered by Shiwani Sawant | 24 Apr, 2020, 01:17: PM

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