CBSE Class 11-science Answered
Asked by suchananag2002 | 02 Sep, 2019, 02:21: PM
Expert Answer
Let AB be the rod of length 4 m . It is supported by two knife edges as shown in figure.
Let each point of support is at a distance x m from centre of mass, symmetrically on both sides of centre of mass.
let us consider g = 10 m/s2 for convenience.
As shown in figure 500 N force is acting downwards at centre of mass due to weight of rod.
To balance a 300 N load at extreme end A, we have , 500 x = 300 (2-x) or x = 0.75 m
Hence maximum distance for each support from respective end, 2-x = 2- 0.75 = 1.25 m
Answered by Thiyagarajan K | 02 Sep, 2019, 04:46: PM
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