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Solve the numerical

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Asked by lovemaan5500 17th March 2018, 5:10 PM
Answered by Expert
Answer:
Given colon
Weight space of space sulphuric space acid equals space 294 space straight g

Molecular space weight space of space straight H subscript 2 SO subscript 4 space equals space 98 space gmmole to the power of negative 1 end exponent

1 right parenthesis space No. space of space moles colon

98 space gmole to the power of negative 1 end exponent equals 1 space mole space of space straight H subscript 2 SO subscript 4

space space space space space 294 space gm space equals apostrophe straight x apostrophe space mole space of space straight H subscript 2 SO subscript 4
space
space space space space space straight x equals 294 over 98

space space space space space straight x equals 3 space moles.

space space space space 294 space gm space of space straight H subscript 2 SO subscript 4 space equals space 3 space moles

2 right parenthesis No. space of space molecules colon

1 space mole space equals space Avogadro apostrophe straight s space no. space of space molcules equals space 6.022 cross times 10 to the power of 23

3 space moles space equals space 6.022 cross times 10 to the power of 23 cross times 3

space space space space space space space space space space space space space space equals 1.80 cross times 10 to the power of 24 space molecules.

3 right parenthesis No. space of space atoms colon

1 space mole space of space straight H subscript 2 SO subscript 4 space space end subscript equals space 2 space moles space of space straight H space atoms space 1 space mole space of space sulphur space atom space and space 4 space moles space of space oxygen space atoms
space space space space space space space space space space space space space space space space space space space space space space space space space space equals 7 space moles space of space atoms
3 space moles space equals space 7 space cross times 3
space space space space space space space space space space space space space equals space 21 space moles space of space atoms.

1 space mole space equals space Avogadro apostrophe straight s space no. space of space space atoms equals space 6.022 cross times 10 to the power of 23

therefore space 21 space moles space equals space space 6.022 cross times 10 to the power of 23 space end exponent space cross times space 21

space space space space space space space space space space space space space space space space space space space equals space 12.6 cross times 10 to the power of 24 space space atoms

Total space number space of space atoms space in space 294 space straight g space of space space straight H subscript 2 SO subscript 4 space space end subscript equals space 12.6 cross times 10 to the power of 24 space space atoms

4 right parenthesis space No. space of space hydrogen space atoms colon
space space space space space
space space space space space 1 space mole space of space space straight H subscript 2 SO subscript 4 space space end subscript equals space 2 space moles space of space hydrogen space atom
space space space space
space space space space space space space 3 space mole space of space space straight H subscript 2 SO subscript 4 space space end subscript equals 6 space space moles space of space hydrogen space atoms

space space space space space space space space space space space space space space space space space space space space space space space space space 1 space mole space equals space space 6.022 cross times 10 to the power of 23 space atoms

space space space space space space space space space space space space space space space space space space space space space space space space space 6 space moles space equals space 6 cross times space 6.022 cross times 10 to the power of 23 space atoms
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 3.61 cross times 10 to the power of 24 space space hydrogen space atoms

therefore 294 space straight g space of space space straight H subscript 2 SO subscript 4 space space end subscript contains space space 3.61 cross times 10 to the power of 24 space space hydrogen space atoms
Answered by Expert 17th March 2018, 7:08 PM
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