CBSE Class 11-science Answered
Solve the following question:
Asked by nkrbasak | 19 Dec, 2011, 09:23: PM
Expert Answer
Two forces acting on the bob are:
a) weight mg acting vertically downward
b) tension T acting along the string
By resolving T in horizontal and vertical direction we find that
T cos 5o = mg
T sin 5o = ma
Dividing both the equations we get:
tan 5o=a/g
a=g tan 5o=10 x 0.087 = 0.87 m/s2
Answered by | 20 Dec, 2011, 09:30: AM
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