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CBSE - XI Science - Physics - Laws of Motion

Solve the following question:

Asked by nkrbasak 29th December 2011, 9:28 PM
Answered by Expert


m= 2kg
coefficient of friction= 0.7 and F=?
as the block is at rest therefore, maximum force of static friction is
fs= coefficient of static friction x R
but R= mgcos30
fs =coefficient of static friction x mg cos30
fs=11.9 N
but in yhis case , actual force of static friction cannot exceed the force due to gravity actind down the plane.
hence, actual force of static frictionis
= mgsin30= 2x9.8x0.5= 9.8 N
Answered by Expert 29th December 2011, 9:52 PM

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