ICSE Class 9 Answered
solve the following numericals
1. A person is listening to a tone of 5 kilohertz at a distance of 450 m from the source of sound find the time interval between successive compressions from the source of sound.
2. A ball is thrown up vertically and IT returns to the thrower after 12 seconds calculate the velocity with which it is thrown up. g is equal to 9.8 metre per second square
3. A ball is thrown upward with a velocity of 49 M per second calculate the total time it needs to return
Asked by bsap6777 | 29 Sep, 2018, 11:46: AM
Expert Answer
Only one question per posting is answered. Hence I answer ony question no. 2
Since the ball return in 12 seconds, it has taken 6 seconds to reach maximum height.
let us use the equation of motion, " v = u-gt " for upward motion in gravitational field,
where u and v are initial and final velocity respectively.g is acceleration due to gravity and t is time taken to travel.
here final velocity is zero when the ball has reached maximum height.
hence we have u = g×t = 9.8×6 = 58.8 m/s
Answered by Thiyagarajan K | 29 Sep, 2018, 12:24: PM
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