Please wait...
Contact Us
Contact
Need assistance? Contact us on below numbers

For Study plan details

10:00 AM to 7:00 PM IST all days.

For Franchisee Enquiry

OR

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this number

93219 24448 / 99871 78554

Mon to Sat - 10 AM to 7 PM

solve

qsnImg
Asked by sarveshvibrantacademy 16th May 2019, 11:45 AM
Answered by Expert
Answer:
For refraction at spherical surface, we have,  begin mathsize 12px style mu over v minus 1 over u equals fraction numerator mu minus 1 over denominator R end fraction end style   .................(1)
where μ is refractive index of spherical medium, v is image distance from pole,
u is object distance from pole and R is radius of curvature.
 
we have μ = 1.5, v = R+(32/3) cm ,  u = -6 cm
 
By substituting the values in eqn.(1), we get , begin mathsize 12px style fraction numerator 1.5 over denominator R plus begin display style 32 over 3 end style end fraction space plus space 1 over 6 space equals space fraction numerator 0.5 over denominator R end fraction end style   ...............(2)
By solving eqn.(2), we get R ≈ 1.74 cm
Answered by Expert 17th May 2019, 5:28 AM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Tags: refraction
Your answer has been posted successfully!

Chat with us on WhatsApp