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CBSE Class 11-science Answered

Solve Question Number 50th both AandB?
Asked by hemanttkumarr | 02 Dec, 2017, 10:03: PM
answered-by-expert Expert Answer
begin mathsize 16px style For space the space 50 straight A space has space already space answered. space straight P space is space length space of space perpendicular space from space the space origin straight p equals fraction numerator open vertical bar negative kcos 2 straight theta close vertical bar over denominator square root of cos squared straight theta plus sin squared straight theta end root end fraction straight p space equals space kcos 2 straight theta Similarly space find space straight q space and space put space it space in space the space LHS space you space will space get space the space RHS. 50 straight B fraction numerator open parentheses 3 minus 2 straight i close parentheses open parentheses 2 plus 3 straight i close parentheses over denominator open parentheses 1 plus 2 straight i right parenthesis left parenthesis 2 minus straight i close parentheses end fraction equals fraction numerator 6 plus 9 straight i minus 4 straight i minus 6 straight i squared over denominator 2 minus straight i plus 4 straight i minus 2 straight i squared end fraction equals fraction numerator 6 plus 5 straight i minus 6 left parenthesis negative 1 right parenthesis over denominator 2 plus 3 straight i minus 2 left parenthesis negative 1 right parenthesis end fraction equals fraction numerator 12 plus 5 straight i over denominator 4 plus 3 straight i end fraction equals fraction numerator 12 plus 5 straight i over denominator 4 plus 3 straight i end fraction cross times fraction numerator 4 minus 3 straight i over denominator 4 minus 3 straight i end fraction equals fraction numerator 48 minus 36 straight i plus 20 straight i minus 15 straight i squared over denominator 16 minus 9 straight i squared end fraction equals fraction numerator 48 minus 16 straight i plus 15 over denominator 16 plus 9 end fraction equals fraction numerator 63 minus 16 straight i over denominator 25 end fraction Conjugate space of space the space complex space number space is space fraction numerator 63 plus 16 straight i over denominator 25 end fraction end style
Answered by Sneha shidid | 03 Dec, 2017, 07:16: PM

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CBSE 11-science - Maths
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CBSE 11-science - Maths
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CBSE 11-science - Maths
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CBSE 11-science - Maths
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CBSE 11-science - Maths
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CBSE 11-science - Maths
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CBSE 11-science - Maths
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CBSE 11-science - Maths
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CBSE 11-science - Maths
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