Solve Q no. 1, 2, 3, 4, 5, 6.
Asked by hariom2083
1st August 2018,
2:29 PM
Answered by Expert
Answer:
Given AP’s are 2 + 5 + 8 .......... upto 50 terms and the series 3 + 5 +7 + 9 ................ upto 100 terms
Let the pth term of the 1st AP is equal to qth term of 2nd AP
Let the pth term of the 1st AP is equal to qth term of 2nd AP
p = 2k and q = 3k - 1
⇒ 2k ≤ 100 and (3k – 1) ≤ 100
⇒ k ≤ 50 and k ≤ 101/3
But k cannot be a fraction
⇒ k ≤ 25 and k ≤ 33
⇒ 2k ≤ 100 and (3k – 1) ≤ 100
⇒ k ≤ 50 and k ≤ 101/3
But k cannot be a fraction
⇒ k ≤ 25 and k ≤ 33
Answered by Expert
6th August 2018,
3:50 PM
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