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Home / Doubts and Solutions/JEE/Physics

Solve problem from this circuit

Asked by venkat 28th October 2017, 2:22 PM
Answered by Expert
Answer:
 
 
 
begin mathsize 12px style fraction numerator 1 over denominator Rp 1 end fraction equals fraction numerator 1 over denominator straight R 1 end fraction plus fraction numerator 1 over denominator straight R 3 end fraction equals 1 over 20 plus 1 fifth Rp 1 equals 4 space Ohms fraction numerator 1 over denominator Rp 2 end fraction equals fraction numerator 1 over denominator straight R 2 end fraction plus fraction numerator 1 over denominator straight R 4 end fraction Also space Rp 2 equals 4 space Ohms Rs equals space Rp 1 plus Rp 2 equals 8 space ohms end style
 
total resistance = 8 ohms
 
 
Potential between C and D
Point C and D are same point therefore potential difference is zero
 
Current through C and D can be obtained using kirchhoff's law as 
20I1-5(I-I1)=0

5(I-I1)+20I1=4
Answered by Expert 7th December 2017, 2:21 PM
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