CBSE Class 11-science Answered
Solve
Asked by reddyJaisaivardhanreddy | 03 Oct, 2020, 02:52: PM
Expert Answer
In top figure , force F1 that makes angle θ with horizontal is pushing the block m . As can be seen from top figure,
by resolving F1 along horizontal and vertical direction, normal reaction force N1 is obtained as
N1 = mg + F1 sinθ
Hence friction force , f1 = μ N1 = μmg + μ F1 sinθ
In figure given at bottom, force F2 that makes angle θ with horizontal is pulling the block m . As can be seen from this figure,
by resolving F2 along horizontal and vertical direction, normal reaction force N2 is obtained as
N2 = mg + F2 sinθ
Hence friction force , f2 = μ N2 = μmg - μ F2 sinθ
Both the blocks are moving with constant speed , we have
F1 cosθ = μmg + μ F1 sinθ
F2 cosθ = μmg - μ F2 sinθ
From above equations, we get
Hence we get the condition F1 > F2
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