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CBSE Class 11-science Answered

solve   :   limit as n rightwards arrow infinity of fraction numerator 1 hat p space plus space 2 hat p space plus....... plus n hat p over denominator n hat left parenthesis p plus 1 right parenthesis end fraction
Asked by Shivendra | 06 Jan, 2019, 01:41: PM
answered-by-expert Expert Answer
begin mathsize 16px style limit as n rightwards arrow infinity of stack space sum with r equals 1 below and n on top r to the power of p over n to the power of p plus 1 end exponent space equals space limit as n rightwards arrow infinity of stack space sum with r equals 1 below and n on top 1 over n open parentheses r over n close parentheses to the power of p space equals space integral subscript 0 superscript 1 x to the power of p d x space equals fraction numerator 1 over denominator p plus 1 end fraction end style
Answered by Thiyagarajan K | 06 Jan, 2019, 03:03: PM

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CBSE 11-science - Maths
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