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Home / Doubts and Solutions/JEE/Mathematics

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Asked by sakshisingh3124 30th June 2018, 9:35 PM
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Answer:
begin mathsize 16px style let space PM space equals straight x increment PMQ tan space straight theta equals PQ over PM equals straight h over straight x................. left parenthesis 1 right parenthesis increment PMR tan space 2 straight theta equals PR over PM equals fraction numerator 3 straight h over denominator straight x end fraction................. left parenthesis 2 right parenthesis from space 1 space and space 2 tan space 2 straight theta equals space 3 space tan space straight theta fraction numerator 2 tanθ over denominator 1 minus tan squared straight theta end fraction equals 3 space tan space straight theta fraction numerator 2 over denominator 1 minus tan squared straight theta end fraction equals 3 fraction numerator 2 over denominator 1 minus begin display style straight h squared over straight x squared end style end fraction equals 3 let space straight h over straight x equals straight t 2 equals 3 minus 3 straight t squared........... left parenthesis 3 right parenthesis 3 straight t squared equals 1 straight t equals straight h over straight x equals fraction numerator 1 over denominator square root of 3 end fraction end style
Answered by Expert 3rd July 2018, 12:14 PM
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