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ICSE Class 9 Answered

Solve for x: 3^logx-2^logx=2^logx+1-3^logx-1
Asked by nithyadiya | 13 Aug, 2018, 07:24: AM
answered-by-expert Expert Answer
3logx - 2logx = 2logx+1 - 3logx-1
Let log x = m
3m - 2m = 2m+1 - 3m - 1 
3m + 3m - 1 = 2m + 1 + 2m 
Solving it we get 
begin mathsize 16px style open parentheses 3 over 2 close parentheses to the power of straight m equals open parentheses 3 over 2 close parentheses squared straight m equals 2 log subscript 10 space straight x space equals space 2 straight x equals 10 squared equals 100 end style
Answered by Sneha shidid | 13 Aug, 2018, 01:35: PM

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