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solve & explain

Asked by Arushi Juyal 13th December 2017, 7:21 AM
Answered by Expert
Answer:
net force begin mathsize 12px style open parentheses B i l space minus space mu m g close parentheses space equals space m space fraction numerator d v over denominator d t end fraction end style
begin mathsize 12px style d v space equals space fraction numerator B i l over denominator m end fraction d t space minus space mu g space d t
v space equals space fraction numerator B l over denominator m end fraction integral subscript 0 superscript a over b end superscript i d t space minus space mu g integral subscript 0 superscript a over b end superscript d t space space space equals space fraction numerator B l over denominator m end fraction integral subscript 0 superscript a over b end superscript open parentheses a t space minus space b t squared close parentheses space d t space minus space mu g a over b

v space equals space fraction numerator B l over denominator m end fraction open curly brackets a over 2 a squared over b squared space minus space b over 3 a cubed over b cubed close curly brackets minus space mu g a over b space equals space space fraction numerator B l over denominator m end fraction open curly brackets fraction numerator a cubed over denominator 2 b squared end fraction space minus space 1 third a cubed over b squared close curly brackets minus space mu g a over b

end style
to stop the rod we make v = 0 and simplify for μ
 
begin mathsize 12px style mu space equals space fraction numerator B l a squared over denominator 6 m g b end fraction end style
 

Answered by Expert 14th December 2017, 5:03 PM
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