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Asked by eknathmote50 | 24 Jun, 2019, 11:21: AM
Expert Answer
Acceleration acting towards surface of imaginary planet is modified because there is an electric force in addition to gravitataional force.
Let a be the modified acceleration .
Time taken T by the ball to reach maximum height is given by , T = v/a ................(1)
where v is initial throwing speed of ball.
If t is time to hit the ground after throwing the ball, t = 2T = 2v/a ....................(2)
net force acting on ball of mass m and charge q :- mg + qE = ma ...................(3)
where E is uniform electric field. from (3) we write electric field E as, E = (m/q) [ a - g ] ..................(4)
If h is maximum height reached by the ball, then we have, h = v2/(2a) .......................(5)
If V is potential difference beween planet surface and maximum height, then we have V = E×h ..........(6)
using eqn.(4) and (5), we rewrite eqn.(6) as , V = (m/q) [ a - g ] × [ v2/(2a) ] .........................(7)
By using the substitution v/a = t/2 using eqn.(2), eqn.(7) can be simplified as, V = [ (mv)/(2q) ] × [ v - (gt/2) ]
Answered by Thiyagarajan K | 24 Jun, 2019, 01:24: PM
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