ICSE Class 8 Answered
Solve:
60x^2y^2+68y^3x-16y^4
Asked by Cl_narayan | 15 Jan, 2020, 10:12: AM
Expert Answer
60x2y2 + 68y3x - 16y4
= 4y2 (15x2 + 17xy - 4y2)
= 4y2 (15x2 + 20xy - 3xy - 4y2)
= 4y2 × [5x(3x + 4y) - y(3x + 4y)]
= 4y2 × (3x + 4y) × (5x - y)
Answered by Yasmeen Khan | 16 Jan, 2020, 03:11: PM
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