Please wait...
Contact Us
Contact
Need assistance? Contact us on below numbers

For Enquiry

9:00am - 9:00pm IST all days.

Business Inquiry (North)

Business Inquiry (West / East / South)

OR

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this number

022-62211530

Mon to Sat - 10 AM to 7 PM

solve

qsnImg
Asked by adjacentcalliber10 18th May 2019, 1:24 PM
Answered by Expert
Answer:
Figure shows the direction of movement of three spheres immediately after cutting the string that connecting A and B.
Due to Tension force and Electrostatic force Ball A and B moves with velocity vA and vB as shown in figure.
Ball C moves with speed vCy along the direction of y-axis.
 
After resolving velocity vectors and applying momentum conservation,  
 
m × vAy + m × vBy + m × vCy = 0 ...................(1)
 
By symmetry, vAy = vBy = v ,  hence from eqn.(1)  we get  vCy = 2 |v|  ....................(2)
 
Final kinetic energy of system = change in potential energy
 
begin mathsize 12px style 1 half m v squared space plus space 1 half m v squared space plus space 1 half m v subscript c Y end subscript superscript 2 space equals space 2 open square brackets fraction numerator Q squared over denominator 4 πε subscript 0 space 2 straight l end fraction space minus space fraction numerator Q squared over denominator 4 πε subscript 0 space straight l end fraction close square brackets space equals space fraction numerator begin display style Q squared end style over denominator begin display style 4 πε subscript 0 space straight l end style end fraction end style  ........................(3)
using eqn.(2) and after simplification, we get  begin mathsize 12px style v subscript C y end subscript superscript 2 space equals space fraction numerator 4 over denominator 3 m end fraction space fraction numerator Q squared over denominator 4 πε subscript 0 space straight l end fraction end style  ....................(4)
By substituting respective values in eqn.(4) , we get vCy = 2√2 m/s
 
Answered by Expert 21st May 2019, 1:37 PM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Tags: speed
Your answer has been posted successfully!

Chat with us on WhatsApp