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CBSE Class 11-science Answered

Solve 5.24 sum plz
question image
Asked by lovemaan5500 | 26 Jan, 2019, 12:57: PM
answered-by-expert Expert Answer
Given:
 
At STP;
 
T = 273 K
 
M of CO2 = 44 g/mol
 
              = 44×10-3 kg/mol
 
R = 8.314 J/mol K
 
We know,
 
Average velocity is given by,
 
straight V subscript Avg space equals space square root of fraction numerator 8 RT over denominator πM end fraction end root space space space space space space space space equals square root of fraction numerator 8 cross times 8.314 cross times 273 over denominator 3.14 cross times 44 cross times 10 to the power of negative 3 end exponent end fraction end root space space space space space space space space equals square root of fraction numerator 18157.776 over denominator 0.1381 end fraction end root space space space space space space space space equals square root of 131482.76 end root space space space space space space space space equals space 362.60 space straight m divided by straight s
 
Answered by Varsha | 29 Jan, 2019, 03:01: PM

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