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Solve:

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Asked by Anish 30th July 2018, 1:06 PM
Answered by Expert
Answer:
begin mathsize 16px style the space condition space is space
straight f left parenthesis 1 right parenthesis space straight f left parenthesis 2 right parenthesis space less than space 0
open parentheses 2 to the power of straight a space minus space 4 to the power of straight a space plus space 2 to the power of straight a space minus 1 close parentheses open parentheses 4.2 to the power of straight a space minus space 2.4 to the power of straight a space plus space 2 to the power of straight a space minus space 1 close parentheses space less than space 0
open parentheses 2 to the power of straight a minus 1 close parentheses squared open parentheses 2.2 to the power of 2 straight a end exponent minus 5.2 to the power of straight a plus 1 close parentheses less than 0
rightwards double arrow 2.2 to the power of 2 straight a end exponent minus 5.2 to the power of straight a plus 1 less than 0
1 half less than 2 to the power of straight a less than 1
log subscript 2 left parenthesis 1 divided by 2 right parenthesis less than straight a space less than space log subscript 2 left parenthesis 1 right parenthesis
minus 1 space less than space straight a space less than space 0 end style
Answered by Expert 30th July 2018, 6:03 PM
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