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CBSE - XII Science - Chemistry

Solid state

Asked by 9th March 2010, 10:33 PM
Answered by Expert

Answer:

B is present on corners and face centres with number of B atoms on face centres along one of the axis are removed.
A is present on body centre and edge centres.

Number of B atoms = 8 x (1/8) + 4 x (1/2) = 3

Number of A atoms  = 12 x (1/4) + 1 = 4

Formula of the compound = A4B3

Answer is C

Answered by Expert 10th March 2010, 4:23 PM

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