Sir
Question no 17 attached
Asked by shobhit
15th May 2018,
9:06 AM
Answered by Expert
Answer:
Figure shows the forces acting on the mass at P and also the resolved components.
From the given dimensions of AB, AP and BP, radius of circular path of the mass can be evaluated as (√3/2)×l .
AP and BP are making an angle 30° with the horizontal plane of circular motion of mass.
The resolved horizontal components of tension in the string acts as centripetal force. Hence we have
T1cos30 + T2cos30 = m×ω2(√3/2)×l
since cos30 = (√3/2), we have T1 + T2 = m×ω2×l
Answered by Expert
15th May 2018,
8:38 PM
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