Ask a Doubt
Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 12-science Answered

Sir plz solve the question.
question image
Asked by Soma | 21 Feb, 2019, 12:03: PM
answered-by-expert Expert Answer
Figure shows various forces acting on a rolling circular object.
Weight which is the force die to acceleration due to gravity is resolved into two components,
one component (mg sinθ) parallele to inclined plane and other one ( mg cosθ) normal to inclined plane.
Normal Reaction force is N and friction force is μN = μ mg cosθ
 
linear acceleration a is obtained from  m×a = (mg sinθ - μ mg cosθ) 
 
Hence linear acceleration a = (g sinθ - μ g cosθ)
 
for rotational motion, Torque τ due to friction force is giving angular acceleration α
 
Hence τ = I×α
 
It is assumed the circular object is having moment of inertia = (1/2)mR2 .
Torque is product of friction force and perpendicular distance which is radius of circular object.
Linear acceleration is R times angular acceleration
 
hence we have,   μ mg cosθ × R = (1/2)mR2 × (g sinθ - μ g cosθ)/R ........................(1)
 
from eqn.(1) we get minimum friction coefficient μ = (1/3)tanθ
Answered by Thiyagarajan K | 21 Feb, 2019, 02:35: PM

Concept Videos

Multiple Choice Questions Practice Test
Answered Unanswered My Questions My Answers
CBSE 12-science - Physics
A dumbbell consists of two masses A and B each of mass m joined by a light rod of length l with mass B attached to a suspension point O by a light rod of length l as shown in figure. Find the minimum required speed with which mass A to be projected horizontally so that the system completes the vertical circular motion.
question image
Asked by artabandhusahu85 | 24 Apr, 2024, 12:07: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Physics
What is charge?
Asked by niharvijayvargiya5 | 23 Apr, 2024, 06:40: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Physics
please resolve with good explanation
question image
Asked by kulhariabhijeet | 21 Apr, 2024, 02:39: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Physics
what are ghost particles please answer how is that not able to interact with other subatomic particles ..?is that faster than photons?
Asked by mohapatraswetalina88 | 21 Apr, 2024, 12:18: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Physics
if breakdown voltage of each capacitor is 40v ,then maximum applied voltage Vmax will be
Asked by aishaisha091098 | 19 Apr, 2024, 04:54: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Physics
explain
question image
Asked by ranadeb8090 | 19 Apr, 2024, 03:32: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Physics
solve option e
question image
Asked by dasrituparna1999 | 13 Apr, 2024, 06:56: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Physics
The number of moles in an elemental sample is just the ratio of the mass m to atomic mass 4. n= A The number of protons N, in an elemental sample is Z (atomic number) times the number of moles of Avogadro's number NA N=ZnN P A Copper has an atomic mass of 63.5 g/mole and 29 protons per atom. If such an atom were neutral, then it would have as many protons as electrons. If you remove electrons from a neutral state, then you get a net positive charge. Given a 54 gram ball of copper with a net charge of 2.2 µC, what fraction of the copper's electrons have been removed?
Asked by dasrituparna1999 | 12 Apr, 2024, 09:26: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Physics
which answer is correct and most appropriate with explanation
question image
Asked by mishrigupta19319 | 08 Apr, 2024, 06:28: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Physics
8212
question image
Asked by madhav9119887644 | 07 Apr, 2024, 08:10: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
My Class Videos Tests ₹ Plans Ask a Doubt
Get Latest Study Material for Academic year 24-25 Click here
×