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Sir plz solve it step by step ,U may leave part (b) but plz solve explaining part(a)

Asked by vishakhachandan026 | 08 Aug, 2019, 10:21: AM

Expert Answer

Given:

For NO,

Volume = 0.25 L

Pressure = 800 torr

equals space 800 over 760 equals 1.05 space atm

temperature = 220 K

By using gas equation, no. of moles can be calculated as,

PV = nRT

straight n equals PV over RT space equals fraction numerator 1.05 cross times 0.25 over denominator 0.0821 cross times 220 end fraction space straight n equals 0.0145 space mol

For O₂

For NO,

Volume = 0.1 L

Pressure = 600 torr

equals space 600 over 760 equals 0.79 space atm

temperature = 220 K

By using gas equation, no. of moles can be calculated as,

PV= nRT

straight n equals PV over RT space space equals fraction numerator 0.79 cross times 0.1 over denominator 0.0821 cross times 220 end fraction straight n equals space 0.00437 space mol

The reaction to form N₂O₄

2NO + O₂ → N₂O₄

2 mole of NO reacts with 1 mole of O₂

so, 0.00437 mole of O₂ will require

fraction numerator space 0.00437 cross times 2 over denominator 1 end fraction equals 0.00874 space mol space of space NO

(a)

Excess of NO is : 0.0.145 - 0.00874 = 0.00578 mole of NO

Now aain by using gas law we can calculate pressure,

PV = nRT

straight P equals nRT over straight V space space space space equals fraction numerator 0.00576 cross times 0.00821 cross times 220 over denominator open parentheses 0.25 plus 0.1 close parentheses end fraction straight P equals 0.299 space atm

(b) From equation,

2 mole of NO gives 1 mole of N₂O₄

so 0.00874 mole of NO will give,

equals fraction numerator 0.00874 cross times 1 over denominator 2 end fraction equals 0.00437 space mole space of space straight N subscript 2 straight O subscript 4

Molar mass of N₂O₄ = 92g/mol

Mass of N₂O₄ = 92×0.00437

= 0.402 gm.

Answered by Varsha | 08 Aug, 2019, 12:52: PM

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