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# Sir plz solve it step by step ,U may leave part (b) but plz solve explaining part(a)

Asked by vishakhachandan026 8th August 2019, 10:21 AM
Given:

For NO,

Volume = 0.25 L

Pressure = 800 torr

temperature = 220 K

By using gas equation, no. of moles can be calculated as,

PV = nRT

For O2
For NO,

Volume = 0.1 L

Pressure = 600 torr

temperature = 220 K
By using gas equation, no. of moles can be calculated as,

PV= nRT

The reaction to form N2O4

2NO + O2 → N2O4

2 mole of NO reacts with 1 mole of  O2

so, 0.00437 mole of  O2 will require

(a)

Excess of NO is : 0.0.145 - 0.00874 = 0.00578 mole of NO

Now aain by using gas law we can calculate pressure,

PV = nRT

(b) From equation,

2 mole of NO gives 1 mole of N2O4

so 0.00874 mole of NO will give,

Molar mass of N2O4 = 92g/mol

Mass of N2O4 = 92×0.00437

= 0.402 gm.

Answered by Expert 8th August 2019, 12:52 PM
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