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JEE Class main Answered

Sir plz solve it step by step,thanks
question image
Asked by vishakhachandan026 | 26 Jun, 2019, 08:47: AM
answered-by-expert Expert Answer
Let the first term and coomon difference be a and r respectively
Therefore, x=ar
S equals fraction numerator a over denominator 1 minus r end fraction comma space minus 1 less than r less than 1
4 equals fraction numerator a over denominator 1 minus r end fraction
rightwards double arrow left parenthesis 1 minus r right parenthesis 4 equals a
rightwards double arrow x equals 4 r left parenthesis 1 minus r right parenthesis
G r a p h space o f space 4 r left parenthesis 1 minus r right parenthesis space i s space g i v e n space b y
So, the minimum value of 4r(1-r) is -8 at r=-1 and maximum is at r=1/2 which is 1
Therefore, range of x is (-8, 1]
Answered by Renu Varma | 26 Jun, 2019, 10:12: AM

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