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Home / Doubts and Solutions/JEE/Mathematics

Sir pls solve this question.

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Asked by rsudipto 15th December 2018, 8:49 AM
Answered by Expert
Answer:
The ways of choosing 3 suits out of 4 = 4C3 
Each suits has 13 cards.
Hence, one card can be chosen from 13 cards = 13C1
n(S) =  52C3
Required probability = 4C3 × 13 × 13 × 13/ 52C3 = 169/425
Answered by Expert 17th December 2018, 10:29 AM
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