Sir, Pls solve this question.
Asked by rsudipto
8th December 2018,
2:53 PM
Answered by Expert
Answer:
Process AB is at constant volume. Hence quanity of heat added per mole = Cv × ΔT = (3/2)R×300 = 450×R Joules
Process CA is at constant pressure. Hence quanity of heat removed per mole = CP × ΔT = (5/2)R×(-150) = -375×R Joules
Answered by Expert
8th December 2018,
10:19 PM
Rate this answer
- 1
- 2
- 3
- 4
- 5
- 6
- 7
- 8
- 9
- 10
You have rated this answer /10
Your answer has been posted successfully!
RELATED STUDY RESOURCES :
Browse free questions and answers by Chapters
- 1 Classification of Elements and Periodicity in Properties
- 2 Chemical Bonding and Molecular Structure
- 3 States of Matter
- 4 Equilibrium
- 5 Hydrogen
- 6 Hydrocarbons
- 7 Environmental Chemistry
- 8 Solutions
- 9 Chemical Kinetics
- 10 Surface Chemistry
- 11 Biomolecules
- 12 Polymers
- 13 Chemistry in Everyday Life
- 14 Atomic Structure
- 15 Chemical Thermodynamics
- 16 Redox Reactions and Electrochemistry
- 17 p-Block Elements
- 18 d - and f - Block Elements
- 19 Some Basic Principles of Organic Chemistry
- 20 Organic Compounds Containing Halogens
- 21 Organic Compounds Containing Oxygen
- 22 Organic Compounds Containing Nitrogen
- 23 Co-ordination Compounds
- 24 Purification and Characterisation of Organic Compounds
- 25 s-Block Element (Alkali and Alkaline Earth Metals)
- 26 Solid State
- 27 Some Basic Concepts in Chemistry
- 28 General Principles and Processes of Isolation of Metals
- 29 Principles Related to Practical Chemistry
Trending Tags
Latest Questions
JEE Main Mathematics
Asked by amaladelsingh
28th October 2020,
10:24 PM
CBSE X Biology
Asked by reenacharan2008
28th October 2020,
9:11 PM
