Contact
Need assistance? Contact us on below numbers

For Study plan details

10:00 AM to 7:00 PM IST all days.

For Franchisee Enquiry

OR

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this number

93219 24448 / 99871 78554

Mon to Sat - 10 AM to 7 PM

# Sir pls solve this question.

Asked by rsudipto 13th December 2018, 10:09 AM
n number of arithmetic means are inserted between a and 2b. Hence in A.P., 2b is (n+2)th term

2b = a + (n+1) d ................(1)

where d is the common difference.

Also we are given that, mth mean, i.e., (m+1)th term in A.P.,  is given by   n = a+md  .............(2)

We eliminate d in eqn.(1), using eqn.(2),   2b = a +(n+1)(n-a)/m  or 2mb = (m-n-1)a + n(n+1) ............(3)

Similarly, n number of arithmetic means are inserted between 2a and b. Hence in A.P., b is (n+2)th term

b = 2a + (n+1) d ................(4)

where d is the common difference.

Also we are given that, mth mean, i.e., (m+1)th term in A.P.,  is given by   n = 2a+md  .............(5)

We eliminate d in eqn.(5), using eqn.(5),   b = 2a +(n+1)(n-2a)/m  or  mb = (m-n-1)2a + n(n+1) ............(6)

By solving the simultaneous linear equations (3) and (6), we get,
Hence ratio of a to b = m : ( n - m + 1)
Answered by Expert 13th December 2018, 4:43 PM
• 1
• 2
• 3
• 4
• 5
• 6
• 7
• 8
• 9
• 10

You have rated this answer /10