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Home / Doubts and Solutions/JEE/Mathematics

Sir pls solve the following.

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Asked by rsudipto 26th December 2018, 11:35 AM
Answered by Expert
Answer:
Use R1 → R1 - R2 and R2 → R2 - R3
Then use formulae to simplify it further
 begin mathsize 16px style sinC minus sinD equals 2 cos open parentheses fraction numerator straight C plus straight D over denominator 2 end fraction close parentheses sin open parentheses fraction numerator straight C minus straight D over denominator 2 end fraction close parentheses cosC minus cosD equals 2 sin open parentheses fraction numerator straight C plus straight D over denominator 2 end fraction close parentheses sin open parentheses fraction numerator straight D minus straight C over denominator 2 end fraction close parentheses Taking space 2 sin open parentheses fraction numerator straight alpha minus straight beta over denominator 2 end fraction close parentheses space from space straight R subscript 1 space and space 2 sin open parentheses fraction numerator straight beta minus straight lambda over denominator 2 end fraction close parentheses space from space straight R subscript 2 Solve space the space determinant space you space will space get space expression space which space is space independent space of space straight theta. end style
Answered by Expert 27th December 2018, 5:25 PM
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