JEE Class main Answered
Sir pls solve the following.
Asked by rsudipto | 05 Jan, 2019, 09:19: AM
Expert Answer
By thereom we can say that in triangle ABC where G is the centroid of the triangle.
AB2 + BC2 + CA2 = 3(GA2 + GB2 + GC2)
Hence, GA2 + GB2 + GC2 = 1/3 (a2 + b2 + c2)
This can be proved using distance formula.
Consider, A(x1, y1), B(x2, y2) and C(x3, y3) hence, 
Assuming that G(0, 0) we will find AB2 + BC2 + CA2 and 3(GA2 + GB2 + GC2) we will get AB2 + BC2 + CA2 = 3(GA2 + GB2 + GC2)
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