JEE Class main Answered
Sir pls solve the following.
Asked by rsudipto | 22 Dec, 2018, 08:09: PM
Expert Answer
Stone is thrown with velocity 25 m/s at an angle 30° with horizontal.
Hence vertical component of velocity is 25×sin30 = 12.5 m/s
Vertical distance travelled = ut+(1/2)gt2 = 12.5×2.5 + (1/2)×9.8×2.5×2.5 ≈ 61.9 m
Height of bridge ≈ 61.9 m
Answered by Thiyagarajan K | 22 Dec, 2018, 09:49: PM
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