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Home / Doubts and Solutions/CBSE/Class 10/Mathematics

Sir, pl. answer my question

Asked by 12th March 2010, 9:47 AM
Answered by Expert
Answer:

3x=cosecθ  then x = cosecθ/3  and 1/x=cotθ/3

Consider 3(x2-1/x2) = 3( cosec2θ / 9 - cot2 θ/9)

=1/3(osec2θ  - cot2 θ)=1/3 (as cosec2θ - cot2 θ=1)

Answered by Expert 12th March 2010, 11:07 AM
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