Sir, pl. answer my question
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12th March 2010,
9:47 AM
Answered by Expert
Answer:
3x=cosecθ then x = cosecθ/3 and 1/x=cotθ/3
Consider 3(x2-1/x2) = 3( cosec2θ / 9 - cot2 θ/9)
=1/3(osec2θ - cot2 θ)=1/3 (as cosec2θ - cot2 θ=1)
Answered by Expert
12th March 2010,
11:07 AM
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