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Junior Class 1 Answered

sir, Monochromatic light is refracted from air into glass of refractive index U. The ratio of wavelength of incident and refracted waves is. Explain it in detail.
Asked by advguptaneeraj4 | 04 May, 2015, 04:22: PM
answered-by-expert Expert Answer

Hi Vishesh,

Let f be the frequency of light.

The frequency of light wave does not change as the light moves from air to glass.

Speed of light wave v is related to both the frequency f and the wavelength l as:

v =f λ

begin mathsize 14px style Let space straight V subscript straight a space and space straight V subscript straight g space be space the space speed space of space light space in space air space and space glass space respectively. Let space straight lambda subscript straight a space and space straight lambda subscript straight g space be space the space wavelength space of space light space wave space in space air space and space in space glass space colon straight i. straight e. space straight lambda subscript straight a space minus wavelength space of space incident space light space wave left parenthesis in space air right parenthesis straight lambda subscript straight g space minus wavelength space of space refracted space light space wave left parenthesis in space glass right parenthesis Therefore space we space can space write colon straight v subscript straight a space equals straight f space straight lambda subscript straight a space space minus negative negative negative negative left parenthesis 1 right parenthesis straight v subscript straight g space equals straight f space straight lambda subscript straight g space space minus negative negative negative negative left parenthesis 2 right parenthesis left parenthesis 1 right parenthesis divided by left parenthesis 2 right parenthesis space gives colon straight v subscript straight a over straight v subscript straight g equals fraction numerator space straight lambda subscript straight a over denominator straight lambda subscript straight g end fraction But space we space know space that space straight v subscript straight a over straight v subscript straight g space equals space refractive space index space straight mu Therefore colon fraction numerator space straight lambda subscript straight a over denominator straight lambda subscript straight g end fraction equals straight mu over 1 straight i. straight e space fraction numerator space straight lambda subscript straight a over denominator straight lambda subscript straight g end fraction equals straight mu colon 1 end style

Answered by | 04 May, 2015, 06:15: PM
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