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sir/mam can you explain me whether this is a problem of basic integration or it comes in the chapter of definite integrstion, because this integration was used during a pronlem in physics. So please tell this to me, because if it requires only basic integration then i can improve myself in that.

Asked by jaychandran1967 27th November 2017, 3:01 PM
Answered by Expert
Answer:
begin mathsize 16px style It space comes space under space basic space integration space as space there space are space no space upper space and space lower space limits space given.
straight I space have space explained space you space the space actual space derivation space using space integration.
We space almost space ue space it space is space as space straight a space formula.
straight d over dx sin to the power of negative 1 end exponent straight x equals fraction numerator 1 over denominator square root of 1 minus straight x squared end root end fraction
Hence comma space integral fraction numerator 1 over denominator square root of 1 minus straight x squared end root end fraction dx equals sin to the power of negative 1 end exponent straight x plus straight c
For space the space Physics space derivation space you space can space use space it space directly.


NOTE colon
You space should space clear space about space basic space integration space then space you space can space easily
do space the space definite space integration. end style
Answered by Expert 27th November 2017, 3:50 PM
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