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Sir/maam how to solve this 2 questions 

Asked by amitjena226 11th December 2017, 10:01 AM
Answered by Expert
Answer:
Time period of Simple Pendulam is given by
 begin mathsize 12px style T space equals space 2 pi square root of l over g end root space end style
T - period, l is length of pendulam and g is acceleration due to gravity. 
 
begin mathsize 12px style g space equals space fraction numerator G M over denominator R squared end fraction end style, G is gravitational constant, M mass of earth and R is earth radius
 
Let g' be the acceleration due to gravity at height R and it is given by
begin mathsize 12px style g apostrophe equals square root of fraction numerator G M over denominator 4 R squared end fraction end root end style
Hence T subscript 2 over T subscript 1 space equals space 2
 
Please ask only one question per post
Answered by Expert 11th December 2017, 11:02 AM
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Tags: gravitation
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