Please wait...
Contact Us
Contact
Need assistance? Contact us on below numbers

For Study plan details

93219 24448 / 89292 63204

10:00 AM to 7:00 PM IST all days.

For Franchisee Enquiry

81783 72169
OR

Chat with us on WhatsApp

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this number

93219 24448 / 99871 78554

Mon to Sat - 10 AM to 7 PM

Home / Doubts and Solutions/NEET/Physics

Sir/maam how to solve this 2 questions 

Asked by amitjena226 11th December 2017, 10:01 AM
Answered by Expert
Answer:
Time period of Simple Pendulam is given by
 begin mathsize 12px style T space equals space 2 pi square root of l over g end root space end style
T - period, l is length of pendulam and g is acceleration due to gravity. 
 
begin mathsize 12px style g space equals space fraction numerator G M over denominator R squared end fraction end style, G is gravitational constant, M mass of earth and R is earth radius
 
Let g' be the acceleration due to gravity at height R and it is given by
begin mathsize 12px style g apostrophe equals square root of fraction numerator G M over denominator 4 R squared end fraction end root end style
Hence T subscript 2 over T subscript 1 space equals space 2
 
Please ask only one question per post
Answered by Expert 11th December 2017, 11:02 AM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer 10/10

Report an issue
Tags: gravitation
Previous Question
Next Question
Your answer has been posted successfully!

Free related questions

what is gravitation
22nd December 2021, 7:39 PM
my doubt is the value of G is 60673multiply10-11power but why we use some no in some different numericals like use of 6.6, some times 6.7 why please ans this ques now 🙏
16th February 2022, 9:24 AM
difference between G , g
21st March 2022, 8:36 AM
gravitation  
27th March 2022, 5:33 PM
Sir,The gravitational due to a uniform disc at a point in its axis is 2GMr/R²((1/r)-(1/√(r²+R²))).Andthe potential at a point in the axis is -2GM/R²(√(R²+r²)-r) where R-radius and r-distance in the axis. Also,We know that on differentiating gravitational potential we get the gravitational field at that point.But that is not the case for disc.On integrating the potential we are not getting the value of the field.Why is it so? Please help
16th May 2022, 9:34 PM
RELATED STUDY RESOURCES :
NEET QUESTION ANSWERS

Browse free questions and answers by Chapters

Trending Tags

trigonometric equations Mole concept linear equations circle trigonometric ratios functions matrix operations integration arithmetic progression quadratic equation

Latest Questions

CBSE X Biology
What is enzyme  
Asked by Sureshgowdayd548 28th October 2020, 10:50 PM
JEE Main Mathematics
The following pseudocode is executed using the “Paragraph words” dataset. At the end of the execution, CountB captures the number of verbs with letter count less than the average letter count of verbs. But the pseudocode may have mistakes in one or more lines. Identify all such lines (if any). It is a Multiple Select Question (MSQ).  Error in Line 4  Error in Line 8  Error in Line 11  Error at Line 12  Error in Line 17  Error at Line 18  Error in Line 21 The following pseudocode is executed using the “Words” table. What will be the value of A at the end of the execution?
Asked by amaladelsingh 28th October 2020, 10:24 PM
CBSE X Biology
I want a brief clarity on Taxonomy
Asked by reenacharan2008 28th October 2020, 9:11 PM

Chat with us on WhatsApp