CBSE Class 11-science Answered
sir i have a question: If in triangle ABC, (tanA-tanB)/(tanA+tanB) = (c-b)/c, prove that A= 60 degree.
Asked by | 12 Aug, 2012, 02:51: PM
Expert Answer
(tanA-tanB?/(tanA+tanB) = (c-b)/c
sin(A-B)/sin(A+B)=(c-b)/c
sin(A-B)/sin(A+B) =(sinC-sinB)/sinC
sin(A-B)/sinC =(sinC-sinB)/sinC (Since, sin(A+B)=sinC)
sin(A-B)=sinC-sinB
sinB = sin(A+B)-sin(A-B) = 2sinBcosA
2cosA=1
cosA=1/2
Thus, angle A = 60 degrees
Answered by | 12 Aug, 2012, 06:48: PM
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